Golang: parse and format unix timestamp
If you have unix timestamp in String
Contents
1. If you have unix timestamp in String
The time.Parse function does not do
Unix timestamps. Instead you can use strconv.ParseIntto parse the string to int64 and create the timestamp with time.Unix:
package main
import (
"fmt"
"time"
"strconv"
)
func main() {
i, err := strconv.ParseInt("1518328047", 10, 64)
if err != nil {
panic(err)
}
tm := time.Unix(i, 0)
fmt.Println(tm)
}
2. If you have unix timestamp in int
The time.Parse function does not do
Unix timestamps.
package main
import (
"fmt"
"time"
)
func main() {
tm := time.Unix(1518328047, 0)
fmt.Println(tm)
}
3. If you want to convert timestamp to RFC3339
Use time.Format and provide time.RFC3339 format
package main
import (
"fmt"
"time"
)
func main() {
unixTimeUTC:=time.Unix(1405544146, 0) //gives unix time stamp in utc
unitTimeInRFC3339 :=unixTimeUTC.Format(time.RFC3339) // converts utc time to RFC3339 format
fmt.Println("unix time stamp in UTC :--->",unixTimeUTC)
fmt.Println("unix time stamp in unitTimeInRFC3339 format :---->",unitTimeInRFC3339)
}